Question

two chords AB and CD of a circle intersect each other at P outside the circle.If AB =6 cm,BP=2cm and PD=2.5 cm,find CD.

Answer 1

Answer:

CD=3.9 cm

Explanation:

We are given two chords AB and CD of a circle intersect each other at P outside the circle.

We have a formula if two chord intersect each other

$AP\times BP=CP\times DP$

where, AB=6 cm, BP=2 cm and PD=2.5 CM

AP=AB+BP

AP=6+2 = 8 cm

Substitute into formula and we get

$8\times 2=CP\times 2.5\\16=2.5CP\\CP=6.4$ cm

CP=CD+DP

6.4=CD+2.5

CD=3.9 cm

Answer 2

Answer:

CD - 3.9 cm

Step-by-step explanation:

See photo