two chords AB and CD of lengths 5cm and 11 cm respectively of a circle are parallel to each other and are on opposite sides of the centre. If the distance between AB and CD is 6 cm find the radius
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Draw OM ⊥ AB and ON ⊥ CD. Join OB and OD.

 (Perpendicular from the centre bisects the chord)

Let ON be x. Therefore, OM will be 6− x.
In ΔMOB,

In ΔNOD,

We have OB = OD (Radii of the same circle)
Therefore, from equation (1) and (2),

From equation (2),

Therefore, the radius of the circle iscm.

 (Perpendicular from the centre bisects the chord)

Let ON be x. Therefore, OM will be 6− x.
In ΔMOB,

In ΔNOD,

We have OB = OD (Radii of the same circle)
Therefore, from equation (1) and (2),

From equation (2),

Therefore, the radius of the circle iscm.
nidhi52:
I'm not getting the calculations
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5
This is ur answer hope it will help u in case of any doubt comment below
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