Two chords AB and CD of the same circle are parallel to each other.P is the centre of the circle .Show that angle CPA=angle DPB
Note: Both chords AB and CD are on the same side of the circle.
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In ∆APB angleBAP=angleABP
{Angle opposite to equal side are equal }
Say=x
Similarly
anglePCD=anglePDC
Say =y
Now PAB=PDC
{ALTERNATE INTERIOR ANGEL}
X=y
Angle BPD=2x
Exterior angle property
AngelAPC=2x
BOTH EQUAL TO 2X SO THEY ARE EQUAL
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