Two chords AB, CD of lengths 5 cm, 11 cm respectively of a circle are parallel. If the distance
between AB and CD is 3 cm, find the radius of the circle.
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Join OA and OC.
Let the radius of the circle be r cm and O be the centre
Draw OP⊥AB and OQ⊥CD.
We know, OQ⊥CD, OP⊥AB and AB∥CD.
Therefore, points P,O and Q are collinear. So, PQ=6 cm.
Let OP=x.
Then, OQ=(6–x) cm.
And OA=OC=r.
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