Two chords intersect at a point on a circle and the diameter through this point bisects the angle between the chords. Prove that the chords have the same length
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Correct option is
A
True
In △OEB&△OEC, they are congruent (SAS)
Three lines are concurrent at E.
Three vertically opposite angles are same. Let them be p, q, r.
BE=EC→(1)
△AEO&DEO are congruent too (SAS)
DE=AE→(2)
Total lengths of chord
AE+EC=DE+EB (Same) (From (1) &(2))
Hence, True.
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