English, asked by arbgamer001, 2 months ago

Two chords, KL and MN, of a circle intersect at an external
point J. If KL = 15 cm. LJ = 5 cm, MN = 21 cm and NJ = 4 cm,
find area(quadrilateral KLNM)
area(AJKM).​

Answers

Answered by rashmisharma83760
0

Explanation:

Two chords KL and MN of a circle intersect at an external point J. If KL= 15 cm, L J =5cm, MN= 21 cm and NJ= 4 cm, then what will be the ratio of the area of the quadrilateral KLNM to the area of the triangle JKM?

Area of triangle JLN = {5*4*sin J}/2 = 10 sin J

Area of triangle JKM = {20*25*sin J}/2 = 250 sin J

Area of quadrilateral KLNM = Area of triangle JKM - Area of triangle JLN

= 250 sin J - 10 sin J

= 240 sin J

Ratio of of the area of the quadrilateral KLNM to the area of the triangle JKM = 240 sin J : 250 sin J

= 24 : 25.

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