Question

Two chords of equal length xy and pq of a circle intersect each other at a if xp is a diameter of the circle and xap is 120° then then what is the distance from centre to point a

Answer 1

Answer:

Let o be the center 2l=length of chord

angle axo = 30

sin 30 = d/l =1/2 where d is the dist of a from center

d=l/2 = one fourth of length of the chord Ans