Two chords of length 20 cm and 24 cm are
drawn perpendicular to each other in a circle
of radius 15cm. What is the distance between
the points of intersection of these chords (in
cm) from the centre of the circle?
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Answer:
Step-by-step explanation:
∴OM
2
=OA
2
−AM
2
=10
2
−8
2
=36
ON
2
=OC
2
−CN
2
=10
2
−(8.5)
2
ON=
100−72.25
=
27.75
∴ Required distance
=OP=
OM
2
+ON
2
=
36+27.75
=
63.75
≈8cm
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