Question

two chords PQ and PR of a circle are equal. prove that the centre of the circle lies on the angle bisector of angle QPR

Answer 1

Answer:ok

Step-by-step explanation:

Answer 2

$\huge\mathfrak\red{Elo!}$

SOLUTION :

In ∆PQX and ∆PRX,
   PQ = PR                   (Given)
   PX = PX                   (common side)
∠OPQ = ∠ OPR          (As PX is the angle bisector of ∠ QPR)

-> So ​∆PQX ≅ ∆PRX      (by S.A.S.)

Therefore QX = XR  So  X is the mid point of chord QR.