Two circle are drawn with the same center .The radius of the longer circle is 10 cm and radius of the smaller circle is 4 cm. Find the area between the two circle.
Answers
Two circle are drawn with the same center .The radius of the longer circle is 10 cm and radius of the smaller circle is 4 cm.
1. Let r1 = 10cm of circle C1 and r2 = 4cm of circle C2
2. Area of C1 = Π(r1)^2
= Π(10)^2
= Π×10×10
= 100Π
3. Area of C2 = Π(r2)^2
= Π(4)^2
= Π×4×4
= 16Π
4. The area between two circle =
Area of C1 - Area of C2
= 100Π - 16Π
= 84Π
Answer:
Step-by-step explanation:Given: SP║RQ, ∠R = 90° and ∠Q = 130°.
To find: The measure of ∠P.
Answer:
It is given that SP║RQ. So let us assume that PQ is the transversal.
Therefore, ∠P + ∠Q = 180° (Co - interior Angles are Supplementary)
∠P + 130° = 180°
∠P = 180° - 130°
∠P = 50°
Now let us assume that SR is the transversal.
Therefore, ∠S + ∠R = 180° (nd radiusf the smaller circle is 4 cm. Find the area between the two circle. of the smaller circle is 4 cm. Find the area between the two circle.
Co - interior Angles are Suppleme of the longer circle is 10 cm and radius of the smaller cirntary)
∠S + 90° = 180°
∠S = 180° - 90°
∠S = 90°