Question

two circle C(O,r) amd C (O,2r) touch each other internally at point P. A chord PQ pf bigger circle meets the smaller circle at M. Show that M bisects PQ

Answer 1

Answer:

Step-by-step explanation:

Hi sis

Let O be the center of smaller circle and O' be center of larger circle.

CD is chord of bigger circle which touches the smaller circle at point N.

Line AMB is common tangent to both the circles.

Postulates to Remember:

1. Perpendicular from center to chord bisects the chord.

2. Line from center of circle to point of contact of tangent makes an angle of 90 degree with the tangent at that point.

O'N ⊥ CD, ON⊥CD, OM⊥AB.

CN=ND

∠CNM=∠DNM=Each being 90°

Line segment NM is common.

ΔCNM ≅ ΔDNM→→[SAS]

So, ∠CMN=∠DMN→→CPCT

Hence , MN bisect angle CMD

I hope it will help you ✌️✌️

Answer 2

Answer:

Step-by-step explanation: