Two circle of raddi at two point,prove that their centres lies on the parpendicular bisect on the common coard
Answers
Answered by
0
Step-by-step explanation:
AB is the common chord of the two circles and OO' is the line segment joining the centres of the two circles. Let OO' intersect AB at P. To prove: OO' is the perpendicular bisector of AB. Hence, OO' is the perpendicular bisector of AB.
Similar questions
Math,
5 months ago
Social Sciences,
5 months ago
Political Science,
11 months ago
English,
11 months ago