Question

two circle of radii 10 and the cm and 8cm intersect and length of common cord is 12 cm find distance between their center​

Answer 1

Answer:

(AC)2=(AD)2+(CD)2    [from pythagorous theorem]

(8cm)2=(AD)2+(6cm)2

(AD)2=(64-36)cm2

        =sqrt{28}

        =2sqrt{7}  

        =2*2.65

        =5.30CM

(CB)2=(CD)2+(BD)2from pythagorous theorem]

(BD)2=(100-36)cm2

       =sqrt{64cm2}

       =8cm

AD+BD=(5.30+8)cm

          =13.30cm(Ans)

HOPE IT HELPED YOU!!!!!!

Step-by-step explanation: