Two circle of radii 5cm and 3cm intersect at two points abd their distance between their centre is 4 cm find the length of the common chord
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let a=5. b=3. c=4
s=a+b+c/2=12/2=6
s-a=1
s-b=3
s-c=2
then we apply heon s formula
√s(s-a)(s-b)(s-c)
then we can find area of triangle
then we can find height(radius. let)
then d =2r
then get answer
s=a+b+c/2=12/2=6
s-a=1
s-b=3
s-c=2
then we apply heon s formula
√s(s-a)(s-b)(s-c)
then we can find area of triangle
then we can find height(radius. let)
then d =2r
then get answer
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