two circle of radius 17 cm and 25 cm intersect each other at two points A and B. if the length of the common chord AB of a circle be 30 cm, find the distance between the centres of the circle.
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Answer:
28 cm
Step-by-step explanation:
Given length of common chord AB = 30 cm
Let the radius of the circle with centre O is OA = 25 cm
Radius of circle with centre P is AP = 17 cm
From the figure, OP⊥ AB
⇒ AC = CB
∴ AC = 15 cm (Since AB = 30 cm)
In ΔACP, AP²= PC²+ AC²
⇒ 17²= PC²+ 15²
⇒ PC² = 289 - 225 = 64
⇒ PC = 8 cm
Consider ΔACO,
AO²= OC²+ AC²
⇒ 25²= OC²+ 15²
⇒ OC = 20 cm
From the figure, OP = OC + PC
= 20 + 8 = 28 cm
Hence, the distance between the centres is 28 cm
Hope it helps!
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