Question

Two circle of radius 5 cm and 3 cm intersect at two point and the distance between their centre is 4 cm. Find the length of the common chord

Answer 1

Hey mate..
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Let two circles with centres O and O’ intersect each other at points A and B. On joining A and B, AB is a common chord.


Here, Radius OA = 5 cm, Radius O’A = 3 cm,

Distance between their centers OO’ = 4 cm

In triangle AOO’,

52 = 42 + 32

=> 25 = 16 + 9

=> 25 = 25

Hence AOO’ is a right triangle, right angled at O’.

Since, perpendicular drawn from the center of the circle bisects the chord.

Hence O’ is the mid-point of the chord AB. Also O’ is the centre of the circle II.

Therefore length of chord AB = Diameter of circle ||

 Length of chord AB = 2 x 3 = 6 cm.

Hope it helps !!

Answer 2

Answer:

Here is the answer

Step-by-step explanation:

Hope it helped u