Two circle with different radius intersect each other in such a way that the centre of smaller circle falls on the circumference of the bigger circle. If angleADC=74 degree ; find the value of angleAOC.
Answers
Answered by
1
see diagram.
∠ADC = 74°
∠ADO = 74°/2 = 37°
In the Isosceles triangle ΔDAO, DA = DO = Radius
∠DOA = (180° - ∠ADO)/2 = 143°/2
ΔDCO is congruent to ΔDAO as the common chord and perpendicular to DO and it is symmetric about DO.
So ∠AOC = 2 * 143°/2 = 143°
∠ADC = 74°
∠ADO = 74°/2 = 37°
In the Isosceles triangle ΔDAO, DA = DO = Radius
∠DOA = (180° - ∠ADO)/2 = 143°/2
ΔDCO is congruent to ΔDAO as the common chord and perpendicular to DO and it is symmetric about DO.
So ∠AOC = 2 * 143°/2 = 143°
Attachments:
kvnmurty:
click on red heart thanks above pls
Similar questions