Question

two circles are drawn inside a big circle of diameter 24 cm diameter of the two circles are 13 and to buy a third of the diameter of the big circle as shown in the adjoining figure find the ratio of the areas of the shaded part to the unshaded part of the circle
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Answer 1

Answer:

Explanation:

the area of a big inside circle =pirsq

d=1/2r

r=12

22/7*12*12= 452.16 area of big circle.

the diameters of small two circle 1/3 and 2/3 respectively

1/3+2/3=24

R=12

1/3*12= R1 =4

2/3*12 = R2=8

area of two small circle =pi(r2+r2)

22/7 (16+64)= 251.2

we need to find out shaded area = area of big circle - areas of two small circle

452.16-251.2= 200.96 ans

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