Question

two circles are drawn inside a big circle of diameter 24 cm diameter of the two circle are 1 by 3 and 2 by 3 of the diameter of the base circle as shown in the adjoining figure find the ratio of the area of the shaded part 2 the unshaded part of the circle

Answer 1

the area of a big inside circle =pirsq

d=1/2r

r=12

22/7*12*12= 452.16 area of big circle.

the diameters of small two circle 1/3 and 2/3 respectively

1/3+2/3=24

R=12

1/3*12= R1 =4

2/3*12 = R2=8

area of two small circle =pi(r2+r2)

22/7 (16+64)= 251.2

we need to find out shaded area = area of big circle - areas of two small circle

452.16-251.2= 200.96 ans

Answer 2

DIMENSIONS OF BIG CIRCLE:-

diameter=24cm

radius=D/2=24/2=12cm

Area of big circle = πr²

π×12×12

π×144=144π

DIMENSIONS OF CIRCLE 1

diameter=1/3×24

=8cm

radius=D/2=8/2=4cm

Area of circle 1=π×4×4

π×16=16π

DIMENSIONS OF CIRCLE 2

diameter=2/3 ×24

=16cm

Radius=D/2=16/2

=8cm

Area of circle 2=π×8×8

π×64=64π

Shaded part=Area of big circle -(Area of circle 1 +Area of circle 2)

144π-(16π+64π)

144π-80π

shaded part=64π

Unshaded part=Area of circle1 +Area of circle2

16π+64π=80π

AREA OF SHADED PART/AREA OF UNSHADED PART

64π/80π (π cut with π)

=64/80

=4/5

RATIO OF AREA=4:5

MARK AS BRAINLIEST