two circles are drawn inside a big circle of diameter 24 cm. the diameter of the two circles are 1/3 and 2/3 of the diameter of the big circle as shown in the adjoining figure.find the ratio of the areas of the shaded part to be unshaded part of the circle.
Answers
Answer:
Step-by-step explanation:
We first calculate the diameters of the two circles.
The first circle = 24 × 1/3 = 8 cm
The second circle = 24 × 2/3 = 16 cm
The areas :
The big circle :
3.142 × 12 × 12 = 452.448 cm squared
The other circles :
3.142 × 8 × 8 = 201.088 cm squared.
3.142 × 4 × 4 = 50.272 cm squared
The unshaded = 452.448 - (201.088 + 50.272)
452.488 - 251.36 = 201.128 cm squared.
Step-by-step explanation:
Area of the big circle = 22/7 x 12 x 12 = 144 pie cm ^2
Diameter of the small circle inside the big circle = 1/3 x 24 = 8
So, radius = 8/2 = 4cm
Diameter of the big circle inside the big circle = 2/3 x 24 = 16
So, radius = 16/2 = 8
Area of the small circle inside the big circle = 22/7 x 4 x 4 = 16 pie cm^2
Area of the big circle inside the big circle = 22/7 x 8 x 8 = 64 pie cm^2
Therefore area of the unshaded part = 64 pie cm^2 + 16 pie cm^2 = 80πcm^2
Area of the shaded part = 144 π cm^2 - 80π cm ^2 = 64πcm^2.
Therefore ratio= 64π is to 80π
cut pie from both side.
so, the ans = 4 is to 5
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