Math, asked by ashishkumar972, 1 year ago

two circles are drawn inside a big circle of diameter 24 cm. the diameter of the two circles are 1/3 and 2/3 of the diameter of the big circle as shown in the adjoining figure.find the ratio of the areas of the shaded part to be unshaded part of the circle.

Answers

Answered by santy2
35

Answer:


Step-by-step explanation:


We first calculate the diameters of the two circles.


The first circle = 24 × 1/3 = 8 cm


The second circle = 24 × 2/3 = 16 cm


The areas :


The big circle :


3.142 × 12 × 12 = 452.448 cm squared


The other circles :


3.142 × 8 × 8 = 201.088 cm squared.


3.142 × 4 × 4 = 50.272 cm squared


The unshaded = 452.448 - (201.088 + 50.272)


452.488 - 251.36 = 201.128 cm squared.

Answered by Shambhabi
16

Step-by-step explanation:

Area of the big circle = 22/7 x 12 x 12 = 144 pie cm ^2

Diameter of the small circle inside the big circle = 1/3 x 24 = 8

So, radius = 8/2 = 4cm

Diameter of the big circle inside the big circle = 2/3 x 24 = 16

So, radius = 16/2 = 8

Area of the small circle inside the big circle = 22/7 x 4 x 4 = 16 pie cm^2

Area of the big circle inside the big circle = 22/7 x 8 x 8 = 64 pie cm^2

Therefore area of the unshaded part = 64 pie cm^2 + 16 pie cm^2 = 80πcm^2

Area of the shaded part = 144 π cm^2 - 80π cm ^2 = 64πcm^2.

Therefore ratio= 64π is to 80π

cut pie from both side.

so, the ans = 4 is to 5

Hopes it help you.

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