Question

Two circles have areas in the ratio 49:8. Find the ratio of their circumference. ​

Answer 1

Step-by-step explanation:

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Answer 2

Let, r1 and r2 be radii of two circles respectively.

Then,

$\frac{\pi {(r1)}^{2} }{\pi {(r2)}^{2} } = \frac{49}{8} \\ \\ ( \frac{r1}{r2})^{2} = \frac{49}{8} \\ \\ \frac{r1}{r2} = \frac{7}{2 \sqrt{2} }$

Now,

$\frac{circumference \: of \: 1st \: circle}{circumfeence \: of \: 2nd \: circle} = \frac{2\pi \: (r1)}{2\pi \: (r2)} \\ = \frac{r1}{r2} = \frac{7}{2 \sqrt{2} }$

∴ Required Ratio = 7 : 2√2

Hope It Helps :)

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