Question

two circles have centre A ,B and intersect each other at points P and Q . Prove that the line joining AB bisects the common chord PQ at right angles

Answer 1

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Answer 2

Answer:

QUESTION  

two circles have centER  A ,B and intersect each other at points P and Q . Prove that the line joining AB bisects the common chord PQ at right angles

TO PROVE

PC=QC

PROOF

IN TRIANGLE PAC AND QAC

AP=QC

PB=QB

AQBP IS A KITE  

SO PQ AND AB INTEREST AT 90  

NOW IN TRIANGLE PAC AND QAC  

ACP=ACQ=90(PROVED ABOVE)

AP=AQ(RADIUS OF SAME CIRCLE)

SO AC=CA (COMMON)

TRIANGLE APC CONGRUNT TRIANGLR ACQ (CPCT)

THEREFORE PC=QC

PROVED

Step-by-step explanation:

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