Question

- Two circles intersect at P and Q. Through P,
a straight line APB is drawn to meet the
circles in A and B. Through Q, a straight line
is drawn to meet the circles at C and D. Prove
that AC is parallel to BD.​

Answer 1

Step-by-step explanation:

Join AC, PQ and BD

ACQP is a cyclic quadrilateral

Angle CAP + angle PQC = 180

Answer 2

Answer:

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