Math, asked by Dhvani58, 9 months ago

two circles intersect at two points B and C. Through B, two line segments ABD and PBQ are drawn to intersect the circles at A,D and P,Q respectively. Prove that angle ACP=angle QCD​

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Answered by vanshika4964
15

Answer:

ANGLE PBQ =ANGLE DBQ (VERTICAL OPP. ANGLES).....1

DRAW A CHORD AP AND DQ

ANGLE PBA = ANGLE PCA ......EQUATION 2

ANGLE DBQ= ANGLE DCQ.....EQUATION 3

BY EQUATION 1,2 3

ANGLE ACP= ANGLE QCD

Answered by Anonymous
5
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ANGLE PBQ =ANGLE DBQ (VERTICAL OPP. ANGLES).....1

DRAW A CHORD AP AND DQ

ANGLE PBA = ANGLE PCA ......EQUATION 2

ANGLE DBQ= ANGLE DCQ.....EQUATION 3

BY EQUATION 1,2 3

ANGLE ACP= ANGLE QCD

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