Question

Two circles intersect at two points B and C.
Through B, two line segments ABD and PBQ
are drawn to intersect the circles at A, D and P,
O respectively (see Fig. 10.40). Prove that
ACP= QCD.​

Answer 1

As we know,

When 2 triangles are similar or congruent then

1. angles are equal
2. sides are equal

In triangles ACP nd QCD,

AC =QC

CP=CD

Therefore,triangleACP~ triangleQCD

then,Angle ACP=Angle QCD

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