Two circles intersect each other at P and Q. If PA and PB are their
diameters respectively, then find ZAQB.
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Answer
Let 0 and O be centers of two
intersecting circle, where
Points of intersection are P and Q
and PA and PB are their diameter
respectively.
join PQ ,AQ and QB
<AQP=90° and <BQP =90°
(Angle in a semicircle is a right
angle)
Adding both these angles
<AQP +<BQP =180°
<AQB=180°
Hence, the points A, Q and B are collinear.
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