Two circles intersect each other at point A and D. Diameters
of two circles are two sides of a triangle prove that point of
Intersection of two circles lies on third side of the circle.
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If circles are drawn taking two sides of a triangle as diameters, prove that the point of intersection of these circles lies on the third side. ... Hence, the circle described on AC as diameter must pass through D. Thus, the two circles intersect in D. Now, ∠ADB + ∠ADC = 180°
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