Two circles of diameters 10 cm and 6 cm have the same centre. A chord of the larger circle is a tangent of the smaller one. The length of the chord is :
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BY PYTH, THOREM
(H)^2 = (P)^2 + (B)^2
==> (10)^2 = (6)^2 + (B)^2
==> 100-36 = B^2
==> 64 - b^2
==> B = 8
SO, 2B = 8*2 = 16
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