Question

Two circles of radii 10 cm and 6 cm are concentric. The length of a chord of the outer circle which touches the inner circle is.

a) 16cm
b) 8cm
c) 24cm​

Answer 1

$\huge{\orange{\underline{\underline{\overline{\bf{\bigstar\;AnSweR:}}}}}}$

We know that tangent and radius are perpendicular at the point of contact.

Also, the perpendicular from center to any chord, bisects the chord.

For the larger circle, we can find the half length of the chord using Pythagoras' theorem.

→ $\bold {\sqrt {10²-6²}}$

→ $\bold {\sqrt {100-36}}$

→ $\bold {\sqrt {64}}$

◕➜ 8cm

So the length of the required chord is

$\Large\tt {2×8=16cm.}$

$\huge\fbox\red {Option\;a\;16cm}$

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