two circles of radii 10 cm and 8 cm intersect and the length of the common chord is 12 cm. find the distance between their centres.
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Answered by
9
hey
_______________
given radius
OP = 10 cm
O'P = 8 cm
•by theorem we know that a line joining from centre to chord is always perpendicular bisector of chord
so PL=LQ = 6cm
now see the attached file
hope helped
_____________________
_______________
given radius
OP = 10 cm
O'P = 8 cm
•by theorem we know that a line joining from centre to chord is always perpendicular bisector of chord
so PL=LQ = 6cm
now see the attached file
hope helped
_____________________
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Answered by
5
Answer:
Center of circles= O and O'
Radii = 10 and 8cm
common chord= PQ
OP= 10cm
O'P = 8cm
PQ= 12cm
PL= 1/2PQ
= 1/2 x 12
= 6cm
In right angle triangle OLP
OP² = OL² + LP²
OL= √OP² - LP²
= √10²- 6²
= √64
= 8cm
In right angle triangle O'LP
O'P²= O'L² - LP²
O'L= √O'P² - LP²
= √8² - 6²
= √28
= 5.29 cm
OO'= 8 + 5.29
= 13.29 cm
Step-by-step explanation: hope it helps u
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