Math, asked by Tons, 1 year ago

Two circles of radii 10cm and 12cm intersect and the length of common chorc is 16cm. Find the distance between their centres.

Hope anyone reply it

Answers

Answered by Anonymous
0
Hi,

Center of circles= O and O'
Radii = 10 and 12cm
common chord= PQ
OP= 10cm
O'P = 12cm
PQ= 16cm
PL= 1/2PQ
= 1/2 x 16
= 8cm

In right angle triangle OLP 

OP² = OL² + LP²
OL= √OP² - LP² 
= √10²- 8²
= √36
= 6cm

In right angle triangle O'LP

O'P²= O'L² - LP²
O'L= √O'P² - LP²
= √12² - 8²
= √80
= 8.94 cm

OO'= 8.94 + 6
= 14.94 cm

Hope it helped u!!
Answered by Aanjali1
0
the distance between their centers r ..
==== 14.94cm
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