Two circles of radii 5.5 cm and 2.2cm respectively touch each other internally. what is the distance between their centers A4.4cm B) 8.8cm C) 2.2 cm D) 8.8 or 2.2cm
Answers
Answered by
0
Answer:
We have
AB=5.6cm,AD=1.4cm,AC=7.2cm and AE=1.8cm.
∴ BD=AB−AD=(5.6−1.4) cm = 4.2 cm
and ,
EC=AC−AE=(7.2−1.8)cm = 5.4cm
Now,
DB
AD
=
4.2
1.4
=
3
1
and
EC
AE
=
5.4
1.8
=
3
1
⇒
DB
AD
=
EC
AE
Thus, DE divides sides AB and AC of △ABC in the same ratio.
Therefore, by the converse of Basic Proportionality Theorem, we have DE∣∣BC
Similar questions