Question

Two circles of radii 8 cm with centre P and Q are given. The chord AB of the circle with centre P and the chord CD of the circle with centre @ are equal. If Z PAB = 40°, then find CQDangle​

Answer 1

The value of ∠CQD is 100°

Given:

Radius of the two circles = 8 cm

chord AB = chord CD

∠PAB = 40°

To Find:

We need to find the value of ∠CQD

Solution:

In the circle with center P, PB will be equal to PA because both are radii of the same circle.

Thus, in triangle PAB, ∠PAB = ∠PBA = 40°

As sum of all the angles of a triangle is 180,

40 + 40 + ∠APB = 180

∠APB = 180 - 80

∠APB = 100

Now, since the two circles are identical and also the two chords are of equal length,

∠APB = ∠CQD = 100

Hence, the value of ∠CQD is 100°

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Answer 2

Step-by-step explanation:

Given

radius of the circle =8cm.

chord AB = chord CD

angle PAB = 40

To find

angle CQD = ?

Sol:

in the triangle with centre P , PB =PA (radii)

ln triangle PAB , angle PAB =angle PBA =40

40 +40 + angle APB =180 ( angle sum property)

angle APB =180 -80

angle APB =100

now ,since the two Circles are identified and also the two chords are of equal length .

ANGLE APB= ANGLE CQD =100 degree.