Question

Two circles of radius 15cm
and 13 cm intersect at A and B
such that AB = 24 cm
The
distance between their
centres is
cm

​

Answer 1

Answer:

We know that,

Because,

OR = OR (Common)

AO = OB (Radii)

AR = BR (Radii)

So,

AM = BM (CPCT)

AM = BM = 24/2 = 12 cm

We can see that AOBR is a Kite,

In ΔBOM,

By Pythagoras theorem,

Therefore,

Similarly in ΔBMR,

Therefore,

Hence,

Distance between their centers,

here your answer

Step-by-step explanation:

We know that,

Because,

OR = OR (Common)

AO = OB (Radii)

AR = BR (Radii)

So,

AM = BM (CPCT)

AM = BM = 24/2 = 12 cm

We can see that AOBR is a Kite,

In ΔBOM,

By Pythagoras theorem,

Therefore,

Similarly in ΔBMR,

Therefore,

Hence,

Distance between their centers,