Two circles of radius R and r touch each other externally and PQ is the direct common tangent. Then PQ square is equal to:
(a) R - r
(b) R = r
(c) 2Rr
(d) 4Rr
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Answered by
16
Answer:
Option (d) is correct.
Explanation:
Two circles of radius R and r
touch each other externally
and PQ is the direct tangent.
Length of the direct common tangent = √d²-(R-r)²
Where,
d = distance between centers of circles
= R-r
PQ² = d² - (R-r)²
= (R+r)² - (R-r)²
= R²+r²+2Rr - (R²+r²-2Rr)
= R²+r²+2Rr-R²-r²+2Rr
= 4Rr
Therefore,
PQ² = 4Rr
•••
Option (d) is correct.
Explanation:
Two circles of radius R and r
touch each other externally
and PQ is the direct tangent.
Length of the direct common tangent = √d²-(R-r)²
Where,
d = distance between centers of circles
= R-r
PQ² = d² - (R-r)²
= (R+r)² - (R-r)²
= R²+r²+2Rr - (R²+r²-2Rr)
= R²+r²+2Rr-R²-r²+2Rr
= 4Rr
Therefore,
PQ² = 4Rr
•••
mahwish270603:
I didn't understand how pq equals root d square minus R-minus r square
Answered by
2
Step-by-step explanation:
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