Two circles of same radius intersect each other at p and q. if the length of the common chord is 30 cm and distance between the centres of the two circles is 40 cm, then what is the radius (in cm) of the circles?answer
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the radius of the circle is 25 cm
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Answer:
Step-by-step explanation:
first given
chord =30 cm
distance=40 cm
i.e centers between two circles is 40 cm
common chord=40 cm
so we can use here Pythagoras theorem a^2+b^2=c^2
so we get c=50
i.e diameter of the circles=50 cm
diameter/2=radius
radius=25 cm
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