Question

Two circles touch each other externally at a point
C and P is a point on the common tangent at C.
If PA and PB are tangents to the two circles, prove
that PA = PB.​

Answer 1

Answer:

We know tangents from external point to circle are circle,

So,

⇒AQ=QP......................(1)

QB=QP.....................(2)

From 1 and 2

⇒AQ=QB

Hence, proved.

Step-by-step explanation:

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