two circles touch Each Other internally show that the tangents drawn to the circle from any point on the common tangents are equal in length.
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Answered by
8
Answer:
Now AO=AC and
AB=AO
thus AB = AC.
Step-by-step explanation:
jiggyasa04:
i did not get that
Answered by
15
☺☺Hello ☺☺
Step-by-step explanation:
Given : AO is a tangent to the circles which intersect each other internally.
Consider the point A,
We construct two tangents AB and AC from point A to the two circles.
Now, AO = AC [Tangents drawn from an external point to the circle are equal in length]
Also, AB = AO [Tangents drawn from an external point to the circle are equal in length]
Thus, AB = AC
Hence, tangents drawn to the two circles (touching each other internally) from any point on the common tangent are equal in length.
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