two circles touch externally the sum of their areas is 130 pie square cm and the distance between their Centre is 14 cm find the radii of the circles
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sum of area is 130
=》pie(r1^2+r2^2)=130
=》r1^2+r2^2=130/3.141=41.38cm sq.
and r1+r2=14cm
(r1+r2)^2=r1^2+r2^2+2r1*r2
=》196=41.48+2r1*r21
=》2r1*r2=154.52cm sq.
now ,
(r1-r2)^2=r1^2+r2^2-2r1*r2
=》(r1-r2)^2=41.38-154.52=-113.14
r1-r2=-10.636cm
r1+r2=14cm
--------------------
=》2r1=3.364
r1=1.682cm
and
r2=12.318cm
so two radious are 1.682cm and 12.318cm
=》pie(r1^2+r2^2)=130
=》r1^2+r2^2=130/3.141=41.38cm sq.
and r1+r2=14cm
(r1+r2)^2=r1^2+r2^2+2r1*r2
=》196=41.48+2r1*r21
=》2r1*r2=154.52cm sq.
now ,
(r1-r2)^2=r1^2+r2^2-2r1*r2
=》(r1-r2)^2=41.38-154.52=-113.14
r1-r2=-10.636cm
r1+r2=14cm
--------------------
=》2r1=3.364
r1=1.682cm
and
r2=12.318cm
so two radious are 1.682cm and 12.318cm
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