Two circles touch externally
the tangent drawn through
contact bisects through AB.
prove that
the point of contact bisects through AB
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I am not completely able to understand your question
Although,in this figure I think you have to prove
BM=AM
here
am=mp-------1 (tangents from an external point m)
bm=mp-------2( tangents from an external point m)
from equations 1 and 2
BM=AM
THUS M BISECTS AB (proved)
please mark it as brainliest
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