Two circles touch internally. The sum of their areas is 116 pi cm^2 and diatance between their centres is is 6cm. Find the radii of the circle.
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Hey here is your answer
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difference of the radii of both circle = 6cm
let the radius of one circle = x
radius of other circle = 6+x
the radius of one circle = x
the area = πr^2
= πx^2
radius of other circle = 6+x
area of circle = πr^2
= π(6+x)^2
= π(6^2 + 2×6×x + x^2 )
= π(36+12x+x^2)
The sum of area of both triangles = 116πcm^2
= πx^2 + π(36+12x+x^2) = 116πcm^2
= π (x^2 + 36 + 12x + x^2) = 116π cm^2
= x^2 + 36 + 12x + x^2 = 116 cm^2
= 2x^2 + 12x + 36 = 116 cm^2
= x = 4
= 6-4 = 2
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hope this helps you
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