Question

Two circles with centre A and B intersect at C and D.Prove that angle ACB=angle ADB

Answer 1

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THE ANSWER IS IN THE ATTACHMENT...

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Answer 2

hi dear.....

Given: Two circles with centres A and B intersect at C and D.

To Prove : ∠ACB = ∠ADB.

Construction:

Join AC, AD, BC, BD and AB.

Proof :

In ∆ACB an ∆ADB,

AC = AD [Radii of the same circle]

BC =BD [Radii of the same circle]

AB = AB [Common] ∴ ∆ACB ≅ ∆ADB [By SSS]

∴ ∠ACB = ∠ADB. [By cpctc].

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