Question

Two Circles with centres O and O' intersect each other at B And D ABC is a straight line meeting two circles At A And C Angle ABD=150° Find value of angleCED​

Answer 1

Answer:

Angle CED = 75°

Step-by-step explanation:

Given :

<AOD = 150°

To find :

<CED

Solution :

Join BD.

< ABD = 1/2 of < AOD = 150/2 = 75°

{ Since angle subtended at the circumference will be half the angle subtended at the center by same/equal arc/chord }

Now, angle ABD = angle CED

{ Since, BCED is a cyclic quadrilateral and exterior angle is equal to its interior opp. angle }

Hence, angle CED = 75°