Question

two circular beads of different sizes are joined together such that the distance between the centres is 14 centimetre the sum of their areas is 130CM square find the radius of each bead

Answer 1

Two circular beads of different sizes are joined together such that the distance between the centres is 14 centimetre the sum of their areas is 130CM square find the radius of each bead?

We have two circles of diff size so,

πr1²+πr2²=130π
π(r1²+r2²)=130π
cancelling π on both sides,
r1²+r2²=130. -(1)
Given,
r1+r2=14
So,
r1=14-r2. -(2)
Sub 2 in 1
(14-r2)²+r2²=130
196-28r2+r2²+r2²=130
2r2²-28r2+66=0. ÷2
r2²-14r2+33=0
r2²-3r2-11r2+33=0
r2(r2-3)-11(r2-3)=0
Therefore,
r2=3(or)11
This implies,
When r1=3 then r2=11,when r1=11 then r2=3.

Answer 2

Answer:

Step-by-step explanation:

Two circular beads of different sizes are joined together such that the distance between the centres is 14 centimetre the sum of their areas is 130CM square find the radius of each bead?

We have two circles of diff size so,

πr1²+πr2²=130π

π(r1²+r2²)=130π

cancelling π on both sides,

r1²+r2²=130. -(1)

Given,

r1+r2=14

So,

r1=14-r2. -(2)

Sub 2 in 1

(14-r2)²+r2²=130

196-28r2+r2²+r2²=130

2r2²-28r2+66=0. ÷2

r2²-14r2+33=0

r2²-3r2-11r2+33=0

r2(r2-3)-11(r2-3)=0

Therefore,

r2=3(or)11

This implies,

When r1=3 then r2=11,when r1=11 then r2=3.