Two circular bronze discs of radii 3cm and 4cm are melted down and cast into a single disc of the same thickness as before. What is the radius of the new disc?
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6
Answer:
vol. of discs
(i) = πr 2h=πx3^2 xh=9πh
(2) = πx4^2 xh=16πh
Total = 25πh
Radius of the new Disc:
πr^2h=25πh
r^2 = 25πh/πh=25
r =v 25 = 5
radius=5cm
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