two circular coils of radii 5 cm and 10 cm carry equal currents of 2A the coils have 50 and 100 turns respectively and are placed in such a way that their planes are perpendicular and the centres coinside ,find the magnetude of the magnetic field B at the common centre ??
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A : `8pixx10^-4T` if currents in the coils are in same sense
B : `4pixx10^-4T` if current in the coils are in opposite sense
C : zero if currents in the coils are in opposite sense
D : `8pixx10^-4` T if currents in the coils are in opposite sense
Correct Answer: A::C
Answer Text
`B_1=(mu_0N_1iI_1)/(2R_1)`
`=((4pixx10^I-7)(50)(2))/(2(5xx10^-2))`
`=4pixx10^-4T`
`B_2=(mu_0N_2i_2)/(2R_2)`
`=((4pixx10^-7)(100)(2))/((2)(10xx10^-2))`
`=4pixx10^-4T`
When currets are in the same direction then
`B_("net")=B_1+B_2`
When curents are in the opposite direction, then
`B_("net")=B_1-B_2`
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