Question

Two circular cone having equal base and heights. If the ratio of thei curve surface is 8:5 then prove that the ratio of their bases and heights is 3:4.​

Answer 1

Answer:

Let r be the radii of bases of cylinder and cone and h be the height

Slant height of cone = √(r^2 + h^2)

∴ 2πrh / πr√(r^2 + h^2) = 8/5

h / √(r^2 + h^2) = 4/5

h2 / (r^2 + h^2) = 16/25

⇒ 25h^2 = 16r^2 + 16h^2

⇒ 9h^2 = 16r^2

⇒ r^2 / h^2 = 9/16

r / h = 3/4

Hence, proved!!!!!!!!!!!

Explanation:

correct your question

right question is:----- a right circular cylinder and cone has equal base and heights. If the ratio of their curved surface area is in the ratio 8:5 then prove that the ratio of their bases and heights is 3:4

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