Question

Two circular cylinders are formed by rolling two rectangular aluminum sheets
each of dimensions 12 m length and 5 m breadth, one by rolling along its length
and the other along its width. Find the ratio of their curved surface areas.




if anyone answer I will mark it as brainliest but quick


step by step explain​

Answer 1

Given:

The dimensions of the rectangular aluminium sheet-

length = 12 m

breadth = 5 m

To find:

The ratio of the curved surface areas of the cylinders

Solution:

Let "C.S.A.₁" & "C.S.A.₂" be the curved surface areas of the two cylinders.

Finding C.S.A. of the cylinder made by rolling along the length of the rectangular sheet

Here

Height of the cylinder = 12 m

Circumference = 5 m

∴ C.S.A.₁ = 2πrh = (Circumference) × (height) = 5 × 12 = 60 m²

Finding C.S.A. of the cylinder made by rolling along the width of the rectangular sheet

Here

Height of the cylinder = 5 m

Circumference of the base= 12 m

∴ C.S.A.₂ = 2πrh = (Circumference) × (height) = 12 × 5 = 60 m²

Finding the ratio of their curved surface areas

∴ The ratio of their area are,

= $\frac{C.S.A._1}{C.S.A._2}$

= $\frac{60\:m^2}{60\:m^2}$

= 1 : 1

Thus, the ratio of the curved surface areas of the cylinders are 1:1.

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