Question

two circular flower beds have been shown on 2 sides of sa
quare lawn of side 56m.If centre of each circular flower beds is point of intersection O of the diagnols of square lawn find sum of areas of lawn and flower beds​

Answer 1

Answer:

Hey mate here is ur answer

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Answer 2

Answer:

Side of square = 56cm

ΔAOB

AB²=OA²+OB²

56²=r² + r²

56×56=2r²

56×56÷2

⇒r²=56×28

Area of flower bed

⇒ Area of 2 sectors + area of 2 triangles

2×∅÷360 + 2×1/2×b×h

90÷180πr² + r² ( we get 90÷180 by cancellation)

1÷2 × 22÷7 ×56×28 + 56×28

88×28 + 56×28

⇒(88+56)×28

⇒144×28= 4032cm²