Question

two circular flower beds have been shown on two sides of a square Law ABCD of side 56 m. If the centre of each circular flower bed is the point of intersection O of the diagonals of the square lawn, find the sum of the areas of the lawn and the flower beds.​

Answer 1

Answer:

Diagonal of a square (AC) =√2×side of a square. Diagonal of a square (AC) =√2 × 56 = 56√2 m. OA= OB = 1/2AC = ½(56√2)= 28√2 m. Hence, the sum of the areas of the lawns and the flower beds are 4032 m²